I had a problem where I had to sort a list where there where values with colons, like chapters or similar in ascending order. If you have a List with dot or comma values instead, you can use the same method. <\/p>\n\n\n\n
The sort order of this would be from the lowest number from the left side and the right side, like this:<\/p>\n\n\n\n
Now it doesn’t seem that difficult, but it took me a while to figure out that there is a built-in class called Version <\/strong>for you to use which is perfect for this. I tried first simply convert and parse them as floats and sort them that way, but this works only until you reach the problem where you have 1:40 and 1:4 and they both would be parsed as 1,4 as the zeroes will be taken away. Same goes for 1:5 and 1:50, they would both be parsed as 1,5 and here as well would be a sorting problem since they are both seen as the same. <\/p>\n\n\n\n So that’s where the Version<\/strong> type comes in, we can parse a string in a version format. So instead of inventing the wheel again, let’s see what we can do with it. <\/p>\n\n\n\n If we want to use the Sort <\/strong>method, we could do it like this. First of all, create a new class, let’s call it MyAwesomeComparer<\/strong>. <\/p>\n\n\n MyObjectWithTheColon<\/strong> is my class I use my items for a List and in it this class, we have a name property, this is the property that contains the values such as above, for example 1:5. So for this to work we need to replace the colon so it becomes dots like this (see code below). Note that if you have a list of values with dots like 1.3, 1.4, then you don’t need to do this obviously. If you have a list of commas, then simply do the same Replace, but instead of replacing comma, replace your comma to a dot.<\/p>\n\n\n We replace the dot and try parse it with the Version<\/strong>.TryParse<\/strong>(), and then we retrive the value to our variable outVerX<\/strong>. We do the same thing for the other parameter y <\/strong>we are comparing and save the value to outVerY<\/strong>, and in the end we return the one who is bigger (see explanation on the int that returns here<\/a>) with the CompareTo <\/strong>from the Version class. We can now use this overridden Comparer like this to get the sorted list!<\/p>\n\n\n <\/p>\n\n\n\n <\/p>\n","protected":false},"excerpt":{"rendered":" I had a problem where I had to sort a list where there where values with colons, like chapters or similar in ascending order. If you have a List with dot or comma values instead, you can use the same method. 1:3 1:4 1:40 1:5 2:4 5:9 4:90 3:500 3:4 1 1:50 The sort order … <\/p>\n\n\tpublic class MyAwesomeComparer : Comparer<MyObjectWithTheColon>\n\t{\n\t\tpublic override int Compare(MyObjectWithTheColon x, MyObjectWithTheColon y)\n\t\t{\n\t\t\tVersion outVerX = new Version();\n\t\t\tVersion.TryParse(x.Name + ".0", out outVerX);\n\n\t\t\tVersion outVerY = new Version();\n\t\t\tVersion.TryParse(y.Name + ".0", out outVerY);\n\n\t\t\treturn outVerX.CompareTo(outVerY);\n\t\t}\n\t}\n<\/pre><\/div>\n\n\n\n\tpublic class MyAwesomeComparer : Comparer<MyObjectWithTheColon>\n\t{\n\t\tpublic override int Compare(MyObjectWithTheColon x, MyObjectWithTheColon y)\n\t\t{\n\t\t\tVersion outVerX = new Version();\n\t\t\tVersion.TryParse(x.Name.Replace(":", ".") + ".0", out outVerX);\n\n\t\t\tVersion outVerY = new Version();\n\t\t\tVersion.TryParse(y.Name.Replace(":", ".") + ".0", out outVerY);\n\n\t\t\treturn outVerX.CompareTo(outVerY);\n\t\t}\n\t}\n<\/pre><\/div>\n\n\n\nMyList.Sort(new MyAwesomeComparer());\n<\/pre><\/div>\n\n\n